create directory based on zip files itself

dear all,

please tell me how create directory based on zip file.

example:

i have 2 zip files. abc.zip , cde.zip.

each of zip files, contains same  files.

abc.zip --contains--> 1.text,2.dat,3.txt

cde.zip --contains--> 1.text,2.dat,3.txt

those zip files @ c:\\zipfolder , have c:\\unzipfolder have prepare accept unzip folder, final result want :

from:

c:\\zipfolder\abc.zip,cde.zip

to be: 

 c:\\unzipfolder\abc\1.text,2.dat,3.txt

and

c:\\unzipfolder\cde\1.text,2.dat,3.txt

thank help.

best  regards,

bambang

hi bambang

you can use zipfile class add reference  system.io.compression.filesystem then use following code snippet:

using system; using system.io.compression;  namespace consoleapplication {     class program     {         static void main(string[] args)         {              string zipfile = @"c:\zipfolder\abc.zip";              //this statement target directory based on input zip file name without extension .zip             string target = @"c:\unzipfolder\" + system.io.path.getfilenamewithoutextension(zipfile);              //extract content target folder (zipfile create destination folder if not exist)             zipfile.extracttodirectory(zipfile, target);              console.readkey();         }       } }

don't forget add a reference to system.io.compression.filesystem library 

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